Question

Which cell will measure standard electrode potential of copper electrode?

पर्याय

• \[\ce{Pt(s) | H2 (g,0.1 bar) | H+ (aq; 1 M) || Cu^{2+} (aq;1M) | Cu}\]

• \[\ce{Pt(s) | H2 (g, 1 bar) | H+ (aq; 1 M) || Cu^{2+} (aq; 2 M) | Cu}\]

• \[\ce{Pt(s) | H2 (g, 1 bar) | H+ (aq; 1 M) || Cu^{2+} (aq; 1 M) | Cu}\]

• \[\ce{Pt(s) | H2 (g, 1 bar) | H+ (aq; 0.1 M) || Cu^{2+} (aq; 1 M) | Cu}\]

Answer 1

\[\ce{Pt(s) | H2 (g, 1 bar) | H+ (aq; 1 M) || Cu^{2+} (aq; 1 M) | Cu}\]

Explanation:

When copper electrode is connected to standard hydrogen electrode, it acts as cathode and its standard electrode potential can be measured.

`"E"^0 = "E"_"R"^0 - "E"_"L"^0 = "E"_"R"^0 - 0 = "E"_"R"^0`

To calculate the standard electrode potential of the given cell it is coupled with the standard hydrogen electrode in which pressure of hydrogen gas is one bar and the cone, of H+ ion in the solution is one molar and also the concentrations of the oxidized and the reduced forms of the species in the right-hand half-cell are unity.