मराठी

Which of the Cannot Be Valid Assignment of Probability for Elementary Events Or Outcomes of Sample Space S = {W1, W2, W3, W4, W5, W6, W7}: Elementary Events: W1 W2 W3 W4 W5 W6 W7 (Ii 1 7 1 7 1 7

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प्रश्न

Which of the cannot be valid assignment of probability for elementary events or outcomes of sample space S =  {w1w2w3w4w5w6w7}:

Elementary events: w1 w2 w3 w4 w5 w6 w7
(ii)
\[\frac{1}{7}\]
\[\frac{1}{7}\]
\[\frac{1}{7}\]
\[\frac{1}{7}\]
\[\frac{1}{7}\]
\[\frac{1}{7}\]
\[\frac{1}{7}\]
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उत्तर

w1 w2 w3 w4 w5 w6 w7
\[\frac{1}{7}\]
\[\frac{1}{7}\]
\[\frac{1}{7}\]
\[\frac{1}{7}\]
\[\frac{1}{7}\]
\[\frac{1}{7}\]
\[\frac{1}{7}\]

   Here, each of the numbers p(ωi) is positive and less than 1.
    ∴ Sum of probabilities = \[p\left( \omega_1 \right) + p\left( \omega_2 \right) + p\left( \omega_3 \right) + p\left( \omega_4 \right) + p\left( \omega_5 \right) + p\left( \omega_6 \right) + p\left( \omega_7 \right)\]

= \[\frac{1}{7} + \frac{1}{7} + \frac{1}{7} + \frac{1}{7} + \frac{1}{7} + \frac{1}{7} + \frac{1}{7} = 7 \times \frac{1}{7} = 1\]

  Thus, the assignment is valid.

 

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पाठ 33: Probability - Exercise 33.3 [पृष्ठ ४८]

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आर.डी. शर्मा Mathematics [English] Class 11
पाठ 33 Probability
Exercise 33.3 | Q 42.2 | पृष्ठ ४८

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