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प्रश्न
When x3 − 2x2 + 6x − k is divided by x − 2, the remainder is −10. The value of k is ______.
पर्याय
20
−20
22
−22
MCQ
रिकाम्या जागा भरा
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उत्तर
When x3 − 2x2 + 6x − k is divided by x − 2, the remainder is −10. The value of k is 22.
Explanation:
Let f(x) = x3 − 2x2 + 6x − k
Now, by the remainder theorem,
f(2) = −10
Step 1: Substitute x = 2 in f(x)
f(2) = 23 − 2(2)2 + 6(2) − k
= 8 − 2(4) + 6(2) − k
= 8 − 8 + 12 − k
= 12 − k
Step 2: Set equal to the remainder
12 − k = −10
Step 3: Solve for k
12 − k = −10
−k = −10 − 12
−k = −22
k = 22
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