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When x3 − 2x2 + 6x − k is divided by x − 2, the remainder is −10. The value of k is ______. - Mathematics

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प्रश्न

When x3 − 2x2 + 6x − k is divided by x − 2, the remainder is −10. The value of k is ______.

विकल्प

  • 20

  • −20

  • 22

  • −22

MCQ
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उत्तर

When x3 − 2x2 + 6x − k is divided by x − 2, the remainder is −10. The value of k is 22.

Explanation:

Let f(x) = x3 − 2x2 + 6x − k

Now, by the remainder theorem,

f(2) = −10

Step 1: Substitute x = 2 in f(x)

f(2) = 23 − 2(2)2 + 6(2) − k

= 8 − 2(4) + 6(2) − k

= 8 − 8 + 12 − k

= 12 − k

Step 2: Set equal to the remainder

12 − k = −10

Step 3: Solve for k

12 − k = −10

−k = −10 − 12

−k = −22

k = 22

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अध्याय 6: Factorisation of polynomials - Exercise 6B [पृष्ठ १०६]

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नूतन Mathematics [English] Class 10 ICSE
अध्याय 6 Factorisation of polynomials
Exercise 6B | Q 1. | पृष्ठ १०६
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