Question

If 3x² + kx − 2 is exactly divisible by x − 1, then the value of k is ______.

पर्याय

• 1

• −1

• 2

• −2

Answer 1

If 3x² + kx − 2 is exactly divisible by x − 1, then the value of k is −1.

Explanation:

Let f(x) = 3x² + kx − 2

f(1) = 0

⇒ 3(1)² + k(1) − 2 = 0

⇒ 3 + k − 2 = 0

⇒ k + 1 = 0

⇒ k = −1