Advertisements
Advertisements
प्रश्न
What is the remedy of hypermetropia?
Advertisements
उत्तर
A hypermetropic eye is corrected by using a convex lens of suitable focal length.
APPEARS IN
संबंधित प्रश्न
Answer the following question in detail.
Obtain the expressions for magnifying power and the length of an astronomical telescope under normal adjustments.
Answer the following question in detail.
What is the limitation in increasing the magnifying powers of a compound microscope?
Discuss about simple microscope and obtain the equations for magnification for near point focusing and normal focusing.
What is the use of an erecting lens in a terrestrial telescope?
What is the use of collimator in a spectrmeter?
What are the uses of spectrometer?
What is the remedy of myopia?
What is hypermetropia?
What is presbyopia?
What is astigmatism? What is its remedy?
Obtain the equation for resolving the power of the microscope.
Mention different parts of the spectrometer.
A compound microscope has a magnifying power of 100 when the image is formed at infinity. The objective has a focal length of 0.5 cm and the tube length is 6.5 cm. What is the focal length of the eyepiece.
If astronomical telescope of length 1.53 m has magnifying power of magnitude 50, the values of fo and fe are ____________.
The magnifying power of a telescope is nine. When it is adjusted for parallel rays, the distance between the objective and eyepiece is 20 cm. The focal length of objective and eyepiece are respectively.
Magnification produced by astronomical telescope for normal adjustment is 10 and length of telescope is 1.1 m. The magnification when the image is formed at least distance of distinct vision (D = 25 cm) is ______.
The image formed by an objective of a compound microscope is ______.
In the adjoining figure, AB represents the incident ray, and BK is the reflected ray. If angle BCF = θ, then ∠BFP is given by ______.
