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Using properties of determinant show that |1logxylogxzlogyx1logyzlogzxlogzy1| = 0 - Mathematics and Statistics

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प्रश्न

Using properties of determinant show that

`|(1, log_x y, log_x z),(log_y x, 1, log_y z),(log_z x, log_z y, 1)|` = 0

बेरीज
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उत्तर

L.H.S. = `|(1, log_x y, log_x z),(log_y x, 1, log_y z),(log_z x, log_z y, 1)|`

= `|(log_"e" x/log_"e" x,log_"e" y/log_"e" x,log_"e" z/log_"e" x),(log_"e" x/log_"e" y,log_"e" y/log_"e" y,log_"e" z/log_"e" y),(log_"e" x/log_"e" z,log_"e" y/log_"e" z,log_"e" z/log_"e" z)| ...[because log_"e" "b" = log_"e" "b"/log_"e" "c"]`

Taking `1/log_"e" x, 1/log_"e" y, 1/log_"e" z` common from R1, R2, R3 respectively, we get

L.H.S. = `1/(log_"e" x*log_"e" y*log_"e" z) |(log_"e" x, log_"e" y, log_"e" z),(log_"e" x, log_"e" y, log_"e" z),(log_"e" x, log_"e" y, log_"e" z)|`

= `1/(log_"e" x*log_"e" y*log_"e" z)(0)` ...[∵ R1, R2, R3 are identical]

= 0

= R.H.S.

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पाठ 4: Determinants and Matrices - Exercise 4.2 [पृष्ठ ६८]

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बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 11 Maharashtra State Board
पाठ 4 Determinants and Matrices
Exercise 4.2 | Q 3. (ii) | पृष्ठ ६८

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