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प्रश्न
Using the monochromatic light of same wavelength in the experimental set-up of the diffraction pattern as well as in the interference pattern where the slit separation is 1 mm, 10 interference fringes are found to be within the central maximum of the diffraction pattern. Determine the width of the single slit, if the screen is kept at the same distance from the slit in the two cases.
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उत्तर
We want a `theta = lambda , theta = lambda/a`
`10 lambda/d = 2 lambda/a a = d/5 = 0.2 `mm
Notice that the wavelength of light and distance of the screen do not enter in the calculation of a.
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संबंधित प्रश्न
A parallel beam of light of wavelength 500 nm falls on a narrow slit and the resulting diffraction pattern is observed on a screen 1 m away. It is observed that the first minimum is at a distance of 2.5 mm from the centre of the screen. Find the width of the slit.
In deriving the single slit diffraction pattern, it was stated that the intensity is zero at angles of nλ/a. Justify this by suitably dividing the slit to bring out the cancellation.
Draw the intensity pattern for single slit diffraction.
State differences between interference and diffraction patterns.
Derive the relation a sin θ = λ for the first minimum of the diffraction pattern produced due to a single slit of width ‘a’ using light of wavelength λ.
Which electric bulb is required for the observation?
What pattern appears when the bulb filament is viewed through the slit?
What happens when the slit is not parallel to the filament?
Why is the fringe pattern wider with a red colour filter?
Why is the fringe pattern narrower with a blue colour filter?
