Advertisements
Advertisements
प्रश्न
Using identities, evaluate 1.05 × 9.5
मूल्यांकन
Advertisements
उत्तर
1.05 × 9.5
`= 105/100 xx 95/10`
`= (105xx95)/1000`
Apply Identity (a + b) (a – b) = a2 – b2
105 × 95 = (100 + 5) (100 – 5)
`= (100)^2 - (5)^2`
= 1000 – 25
= 9975
`1.05 xx9.5```
`=9975/1000```
= 9.975
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
संबंधित प्रश्न
Use a suitable identity to get the following products.
(6x − 7) (6x + 7)
Use a suitable identity to get the following products.
`(x/2 + (3y)/4)(x/2 + (3y)/4)`
Using identities, evaluate 9982
Using identities, evaluate 78 × 82
Expand the following square, using suitable identities
(2x + 5)2
Factorise the following using suitable identity
a2 + 6ab + 9b2 – c2
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
a2x3 + 2abx2 + b2x
Factorise the following.
x2 + 9x + 20
Factorise the following.
y2 + 7y + 12
If p + q = 12 and pq = 22, then find p2 + q2.
