Advertisements
Advertisements
प्रश्न
Use a suitable identity to get the following products
(2a − 7) (2a − 7)
Advertisements
उत्तर
(2a − 7) (2a − 7) = (2a − 7)2
= (2a)2 − 2(2a) (7) + (7)2 [(a − b)2 = a2 − 2ab + b2]
= 4a2 − 28a + 49
संबंधित प्रश्न
Using identities, evaluate 1.05 × 9.5
Using (x + a) (x + b) = x2 + (a + b) x + ab, find 103 × 104
Expand `("x"+1/2)^2`
`(("a" + "b")("a"^3 - "b"^3))/(("a"^2 - "b"^2))` = ___________
Simplify: (a + b)2 – 4ab
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
4x4 + 12x3 + 9x2
The cost of a chocolate is Rs (x + y) and Rohit bought (x + y) chocolates. Find the total amount paid by him in terms of x. If x = 10, find the amount paid by him.
What should be added to 4c(– a + b + c) to obtain 3a(a + b + c) – 2b(a – b + c)?
Factorise `x^2 + 1/x^2 + 2 - 3x - 3/x`.
Take suitable number of cards given in the adjoining diagram [G(x × x) representing x2, R(x × 1) representing x and Y(1 × 1) representing 1] to factorise the following expressions, by arranging the cards in the form of rectangles: x2 + 4x + 4. Factorise 2x2 + 6x + 4 by using the figure.
Calculate the area of figure.
