Advertisements
Advertisements
प्रश्न
Factorise p4 + q4 + p2q2.
Advertisements
उत्तर
We have, p4 + q4 + p2q2
= p4 + q4 + 2p2q2 – 2p2q2 + p2q2 ...[Adding and subtracting 2p2q2]
= p4 + q4 + 2p2q2 – p2q2
= [(p2)2 + (q2)2 + 2p2q2] – p2q2 ...[Using the identity, a2 + b2 + 2ab = (a + b)2]
= (p2 + q2)2 – (pq)2
= (p2 + q2 + pq)(p2 + q2 – pq) ...[Using the identity, a2 – b2 = (a + b)(a – b)]
APPEARS IN
संबंधित प्रश्न
Simplify (ab + bc)2 − 2ab2c
Using (x + a) (x + b) = x2 + (a + b) x + ab, find 103 × 104
Expand (ax + by)2
Use an expansion formula to find the value.
(997)2
Factors of 9x2 + 6xy are
Expand the following square, using suitable identities
(mn + 3p)2
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
`x^2/4 + 2x + 4`
Factorise the following.
x2 + 9x + 20
Factorise the following.
y2 + 7y + 12
Verify the following:
(7p – 13q)2 + 364pq = (7p + 13q)2
