Advertisements
Advertisements
प्रश्न
Using identities, evaluate 712
Advertisements
उत्तर
712 = (70 + 1)2
= (70)2 + 2(70) (1) + (1)2 [(a + b)2 = a2 + 2ab + b2 ]
= 4900 + 140 + 1 = 5041
संबंधित प्रश्न
Expand:
(2a – 3b)2
Use a formula to multiply of (4z – 5y)(4z + 5y)
`(("a" + "b")("a"^3 - "b"^3))/(("a"^2 - "b"^2))` = ___________
Factorise the following expressions
x2 + 14x + 49
Using identity, find the value of (100.1)2
The sum of areas of two squares with sides 4a and 4b is ______.
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
9x2 + 24x + 16
Verify the following:
(5x + 8)2 – 160x = (5x – 8)2
Find the length of the side of the given square if area of the square is 625 square units and then find the value of x.
Take suitable number of cards given in the adjoining diagram [G(x × x) representing x2, R(x × 1) representing x and Y(1 × 1) representing 1] to factorise the following expressions, by arranging the cards in the form of rectangles: x2 + 4x + 4. Factorise 2x2 + 6x + 4 by using the figure.
Calculate the area of figure.
