मराठी

Use Newton'S Second Law Of Motion to Explain the Following Instance : You Pull Your Hands Back While Catching a Fast Moving Cricket Ball.Use

Advertisements
Advertisements

प्रश्न

Use Newton's second law of motion to explain the following instance : 

A cricketer pulls his hands back while catching a fast moving cricket ball .

टीपा लिहा
Advertisements

उत्तर

We pull our hands back while catching a fast moving cricket ball, because by doing so, we increase the time of catch, i.e. increase the time to bring about a given change in momentum, and hence, the rate of change of momentum decreases. Thus, a small force is exerted on our hands by the ball.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Laws of Motion - Exercise 3 (C) [पृष्ठ ६९]

APPEARS IN

सेलिना Concise Physics [English] Class 9 ICSE
पाठ 3 Laws of Motion
Exercise 3 (C) | Q 18.1 | पृष्ठ ६९

संबंधित प्रश्‍न

A constant retarding force of 50 N is applied to a body of mass 20 kg moving initially with a speed of 15 ms–1. How long does the body take to stop?


If the tension in the cable supporting an elevator is equal to the weight of the elevator, the elevator may be
(a) going up with increasing speed
(b) going down with increasing speed
(c) going up with uniform speed
(d) going down with uniform speed


In a simple Atwood machine, two unequal masses m1 and m2 are connected by a string going over a clamped light smooth pulley. In a typical arrangement (In the following figure), m1 = 300 g and m2 = 600 g. The system is released from rest. (a) Find the distance travelled by the first block in the first two seconds; (b) find the tension in the string; (c) find the force exerted by the clamp on the pulley.


A constant force F = m2g/2 is applied on the block of mass m1 as shown in the following figure. The string and the pulley are light and the surface of the table is smooth. Find the acceleration of m1.


Find the mass M of the hanging block in the following figure that will prevent the smaller block from slipping over the triangular block. All the surfaces are frictionless and the strings and the pulleys are light.


A force of 10 N acts on a body of mass 2 kg for 3 s, initially at rest. Calculate : Change in momentum of the body.


A pebble is thrown vertically upwards with a speed of 20 m s-1. How high will it be after 2 s? (Take g = 10 m s-2)


A stone is thrown vertically upward with a velocity of 9.8 m/s. When will it reach the ground?


The position time graph of a body of mass 2 kg is as given in figure. What is the impulse on the body at t = 0 s and t = 4 s.


Figure shows (x, t), (y, t ) diagram of a particle moving in 2-dimensions.


(a)


(b)

If the particle has a mass of 500 g, find the force (direction and magnitude) acting on the particle.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×