Advertisements
Advertisements
प्रश्न
Two long straight parallel conductors carrying currents I1 and I2 are separated by a distance d. If the currents are flowing in the same direction, show how the magnetic field produced by one exerts an attractive force on the other. Obtain the expression for this force and hence define 1 ampere.
Advertisements
उत्तर
Fab = Force experienced by wire 'a' of length 'l' due to the magnetic field of wire 'b'
Fba = Force experienced by wire 'a' of length 'l' due to the magnetic field of wire 'b'
Ba = Magnetic field due to wire 'a'
Bb = Magnetic field due to wire 'b'
Ba = `(mu_0I_a)/(2rd)`
Since `vecF = i(vecl xx vecB)`
`F_(ba) = I_1. l(mu_0I_2)/(2rd)`
Similarly, `F(ab) = I_1.l(mu_0I_2)/(2rd)`
The direction of force experienced by wire 'a' is toward wire 'b'. (As shown in the diagram).
Similarly, the direction of force experienced by wire 'b' is toward wire 'a'. Thus, the force is attractive.
If two long wires are placed in a vacuum at a separation of 1 m, one Ampere would be defined as the current in each wire that would produce a force of 2 × 10–7Nm–1 per unit length of wire.
APPEARS IN
संबंधित प्रश्न
Two infinitely long straight parallel wires, '1' and '2', carrying steady currents I1 and I2 in the same direction are separated by a distance d. Obtain the expression for the magnetic field `vecB`due to the wire '1' acting on wire '2'. Hence find out, with the help of a suitable diagram, the magnitude and direction of this force per unit length on wire '2' due to wire '1'. How does the nature of this force changes if the currents are in opposite direction? Use this expression to define the S.I. unit of current.
Two long and parallel straight wires A and B carrying currents of 8.0 A and 5.0 A in the same direction are separated by a distance of 4.0 cm. Estimate the force on a 10 cm section of wire A.
Two parallel, long wires carry currents i1 and i2 with i1 > i2. When the currents are in the same direction, the magnetic field at a point midway between the wires is 10 µT. If the direction of i2 is reversed, the field becomes 30 µT. The ratio i1/i2 is
A long, straight wire carrying a current of 1.0 A is placed horizontally in a uniform magnetic field B = 1.0 × 10−5 T pointing vertically upward figure. Find the magnitude of the resultant magnetic field at the points P and Q, both situated at a distance of 2.0 cm from the wire in the same horizontal plane.
Two parallel wires carry equal currents of 10 A along the same direction and are separated by a distance of 2.0 cm. Find the magnetic field at a point which is 2.0 cm away from each of these wires.
Four long, straight wires, each carrying a current of 5.0 A, are placed in a plane as shown in figure. The points of intersection form a square of side 5.0 cm.
(a) Find the magnetic field at the centre P of the square.
(b) Q1, Q2, Q3, and Q4, are points situated on the diagonals of the square and at a distance from P that is equal to the diagonal of the square. Find the magnetic fields at these points.
A long, straight wire carries a current i. Let B1 be the magnetic field at a point P at a distance d from the wire. Consider a section of length l of this wire such that the point P lies on a perpendicular bisector of the section B2 be the magnetic field at this point due to this second only. Find the value of d/l so that B2 differs from B1 by 1%.
If a current I is flowing in a straight wire parallel to x-axis and magnetic field is there in the y-axis then, ______.
Three infinitely long parallel straight current-carrying wires A, B and C are kept at equal distance from each other as shown in the figure. The wire C experiences net force F. The net force on wire C, when the current in wire A is reversed will be ______.
Two long parallel wires kept 2 m apart carry 3A current each, in the same direction. The force per unit length on one wire due to the other is ______.
