Advertisements
Advertisements
प्रश्न
Two bulbs are rated 60 W, 220 V and 60 W, 110 V respectively. Calculate the ratio of their resistances.
Advertisements
उत्तर
Given,
Voltage, V1 = 220 V
V2 = 110 V
Power, P1 = P2 = P = 60 W
As R = `"V"^2/"P"`
`"R"_1 = "V"_1^2/"P" = (220 xx 220)/60`
`"R"_2 = "V"_2^2/"P" = (110 xx 110)/60`
On dividing R1 and R2
`"R"_1/"R"_2 = ((220 xx 220)/60)/((110 xx 110)/60)`
= `4/1`
`"R"_1 : "R"_2 = 4 : 1`
APPEARS IN
संबंधित प्रश्न
S.I. unit and commercial unit of electrical energy are same.
In a household electrical circuit, the appliance are connected in ............with the mains.
The purpose of an electric meter in a house is
State the purpose of kWh meter.
One day the meter reading is found to be 7643 units while the next day, it was 7657 units. What is the consumption of electricity in a day?
What is an electric fuse? State its purpose in the household electrical circuit.
An electric iron of power 1.5 kW is used for 30 minutes to press the clothes. Calculate the electrical energy consumed in
- kilowatt-hour
- joule.
In a premise 5 bulbs each of 100 W, 2 fans each of 60 W, 2 A.Cs each of 1.5 kW is used for 5 h per day. Find:
- Total power consumed per day,
- Total power consumed in 30 days,
- Total electrical energy consumed in 30 days.
- The cost of electricity at the rate of ₹ 6.25 per unit.
State and define the household unit of electricity.
An electrical appliance is rated as 60 W – 150 V.
How much current will flow through the appliance when in use?
