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Two bodies of unequal mass are moving in the same direction with equal kinetic energy. The two bodies are brought to rest by applying retarding force of same magnitude.

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प्रश्न

Two bodies of unequal mass are moving in the same direction with equal kinetic energy. The two bodies are brought to rest by applying retarding force of same magnitude. How would the distance moved by them before coming to rest compare?

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उत्तर

According to the work-energy theorem,

Change in KE is equal to work done by all the forces acting on the body. Let us assume that only one force (retarding force) is acting on the body, therefore,

KE of the body = Work done by retarding force KE of the body = Retarding force × Displacement

As the KE of the bodies and retarding forces applied to them are the same, therefore, both bodies will travel equal distances before coming to rest.

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पाठ 6: Work, Energy and Power - Exercises [पृष्ठ ४६]

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एनसीईआरटी एक्झांप्लर Physics Exemplar [English] Class 11
पाठ 6 Work, Energy and Power
Exercises | Q 6.32 | पृष्ठ ४६

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