Advertisements
Advertisements
प्रश्न
Three solid cubes of edges 6 cm, 10 cm, and x cm are melted to form a single cube of edge 12 cm, find the value of x.
Advertisements
उत्तर
Edge of first cube = 6 cm
Volume = (6)3 = 216 cm3
Edge of second cube = 10 cm
Volume = (10)3 = 1000 cm3
Edge of third cube = x
Volume =x3
Edge of resulting cube = 12 cm
Volume = (12)3 = 1728 cm3
216 + 1000 + x3 = 1728
x3 = 1728 – 216 – 1000 = 512 = (8)3
x = 8
Edge of third cube = 8 cm
APPEARS IN
संबंधित प्रश्न
Suppose that there are two cubes, having edges 2 cm and 4 cm, respectively. Find the volumes V1and V2 of the cubes and compare them.
Find the volume in cubic decimetre of the cube whose side is 75 cm.
Find the surface area of a cube whose edge is 2.1 m.
The square on the diagonal of a cube has an area of 1875 sq. cm. Calculate:
(i) The side of the cube.
(ii) The total surface area of the cube.
The edges of three cubes of metal are 3 cm, 4 cm, and 5 cm. They are melted and formed into a single cube. Find the edge of the new cube.
Each face of a cube has a perimeter equal to 32 cm. Find its surface area and its volume.
The length of the diagonals of a cube is 8√3 cm.
Find its:
(i) edge
(ii) total surface area
(iii) Volume
The ratio between the lengths of the edges of two cubes is in the ratio 3: 2. Find the ratio between their:
(i) total surface area
(ii) volume.
The lateral surface area of a cube of side 12 cm is
A cube of side 3 cm painted on all its faces, when sliced into 1 cubic centimetre cubes, will have exactly 1 cube with none of its faces painted.
