Advertisements
Advertisements
प्रश्न
There is a slide in the park. One of its side walls has been painted in some colour with a message “KEEP THE PARK GREEN AND CLEAN” (see the given figure). If the sides of the wall are 15m, 11m, and 6m, find the area painted in colour.

Advertisements
उत्तर
It can be observed that the area to be painted in colour is a triangle, with sides of 11 m, 6 m, and 15 m.
Perimeter of such a triangle = (11 + 6 + 15) m
2 s = 32 m
s = `32/2 m`
s = 16 m
By Heron’s formula,
Area of Triangle = `sqrt(s(s-a)(s-b)(s-c))`
= `[sqrt(16(16-11)(16-6)(16-15))]m^2`
= `(sqrt(16xx5xx10xx1))m^2`
= `20sqrt2m^2`
Therefore, the area painted in colour is `20sqrt2m^2`.
APPEARS IN
संबंधित प्रश्न
An isosceles triangle has perimeter 30 cm and each of the equal sides is 12 cm. Find the area of the triangle.
The perimeter of an isosceles triangle is 42 cm and its baše is (32) times each of the equal sides. Find the length of each side of the triangle, area of the triangle and the height of the triangle.
A rhombus sheet, whose perimeter is 32 m and whose one diagonal is 10 m long, is painted on both sides at the rate of Rs 5 per m2. Find the cost of painting.
Find the area of a triangle whose base and altitude are 5 cm and 4 cm respectively.
Using Heron’s formula, find the area of a triangle whose sides are 10 cm, 24 cm, 26 cm
Find the area of an equilateral triangle whose perimeter is 180 cm
Find the area of the unshaded region
The perimeter of an equilateral triangle is 30 cm. The area is
If the side of a rhombus is 10 cm and one diagonal is 16 cm, the area of the rhombus is 96 cm2.
The perimeter of a triangular field is 420 m and its sides are in the ratio 6 : 7 : 8. Find the area of the triangular field.
