Advertisements
Advertisements
प्रश्न
The area of triangle formed by the points (− 5, 0), (0, – 5) and (5, 0) is
पर्याय
0 sq.units
25 sq.units
5 sq.units
none of these
Advertisements
उत्तर
25 sq.units
Explanation;
Hint:
Area of the ∆

= `1/2[25 + 0 + 0 - (0 - 25 + 0)]`
= `1/2[25 + 25]`
⇒ `1/2 xx 50`
= 25 sq.units
APPEARS IN
संबंधित प्रश्न
Find the area of a triangle whose base and altitude are 5 cm and 4 cm respectively.
Find the area of an isosceles triangle having the base x cm and one side y cm.
Find the areas of the given plot. (All measures are in metres.)

Find the area of the triangle formed by the points
(–10, –4), (–8, –1) and (–3, –5)
Determine whether the sets of points are collinear?
(a, b + c), (b, c + a) and (c, a + b)
Using Heron’s formula, find the area of a triangle whose sides are 10 cm, 24 cm, 26 cm
An advertisement board is in the form of an isosceles triangle with perimeter 36 m and each of the equal sides are 13 m. Find the cost of painting it at ₹ 17.50 per square metre.
The area of the isosceles triangle is `5/4 sqrt(11)` cm2, if the perimeter is 11 cm and the base is 5 cm.
If the side of a rhombus is 10 cm and one diagonal is 16 cm, the area of the rhombus is 96 cm2.
The triangular side walls of a flyover have been used for advertisements. The sides of the walls are 13 m, 14 m and 15 m. The advertisements yield an earning of Rs 2000 per m2 a year. A company hired one of its walls for 6 months. How much rent did it pay?
