Question

There are two cuboidal boxes as shown in the adjoining figure. Which box requires the lesser amount of material to make?

(a)	(b)

Answer 1

For this we find their areas -

(a) Length of the first box (l) = 60 cm

Width of first box (b) = 40 cm

Height of first box (h) = 50 cm

Total surface area of first box = 2(lb + bh + hl)

= 2(60 × 40 + 40 × 50 + 50 × 60)

= 2(2400 + 2000 + 3000)

= 2 × 7400

= 14800 cm²

(b) Length of the second box (l) = 50 cm

Width of second box (D) = 50 cm

Height of second box (h) = 50 cm

Total surface area of second box = 2(lb + bh + hl)

= 2(50 × 50 + 50 × 50 + 50 × 50)

= 2(2500 + 2500 + 2500)

= 2 × 7500

= 15000 cm²

Here the area of the first box is less. Hence, less material is required to make it.