Advertisements
Advertisements
प्रश्न
The zeroes of the quadratic polynomial 16x2 – 9 are ______.
पर्याय
`3/4, 3/4`
`-3/4, 3/4`
`9/16, 9/16`
`-3/4, -3/4`
Advertisements
उत्तर
The zeroes of the quadratic polynomial 16x2 – 9 are `underlinebb(-3/4, 3/4)`.
Explanation:
16x2 – 9 = 0
(4x – 3)(4x + 3) = 0
∴ x = `± 3/4`
संबंधित प्रश्न
The graphs of y = p(x) are given in following figure, for some polynomials p(x). Find the number of zeroes of p(x).
Find the zeroes of the quadratic polynomial `f(x) = x^2 + 3x ˗ 10` and verify the relation between its zeroes and coefficients.
Find the zeroes of the quadratic polynomial `f(x) = 5x^2 ˗ 4 ˗ 8x` and verify the relationship between the zeroes and coefficients of the given polynomial.
Obtain all other zeroes of `(x^4 + 4x^3 – 2x^2 – 20x – 15)` if two of its zeroes are `sqrt5 and –sqrt5.`
Find all the zeroes of polynomial `(2x^4 – 11x^3 + 7x^2 + 13x – 7)`, it being given that two of its zeroes are `(3 + sqrt2) and (3 – sqrt2)`.
If the zeroes of the polynomial `f(x) = x^3 – 3x^2 + x + 1` are (a – b), a and (a + b), find the values of a and b.
If one zero of the quadratic polynomial x2 + 3x + k is 2, then the value of k is ______.
If x3 + 11 is divided by x2 – 3, then the possible degree of remainder is ______.
A polynomial of degree n has ______.
The number of polynomials having zeroes – 3 and 4 is ______.
