Advertisements
Advertisements
प्रश्न
The work done by a force acting obliquely is given by the formula : W = F cos θ ✕ s. What will happen to the work done if angle θ between the direction of force and motion of the body is increased gradually? Will it increase, decrease or remain constant.
Advertisements
उत्तर
The relation between work, force, distance and angle between the two is:
W = (F) (S) cos θ
Where,
(W) - Work done
(F) - Force
(S) - Displacement
(θ) - Angle between force and displacement
Let us see the graph of to understand the dependence of work on the angle between force and distance.
From the graph, we can observe that on increasing the value of angle between force and distance, value of cos θ continuously decreases and becomes negative after `pi/2`.
Hence, if we increase the angle between force and distance gradually, the value of work done will continuously decrease.
APPEARS IN
संबंधित प्रश्न
A force of 7 N acts on an object. The displacement is, say 8 m, in the direction of the force (see the given figure). Let us take it that the force acts on the object through the displacement. What is the work done in this case?

Define work.
It takes 20 s for a person A of mass 50 kg to climb up the stairs, while another person B does the same in 15 s. Compare the work done.
Find the kinetic energy of a body of mass 1 kg moving with a uniform velocity of 10 m s-1.
Is the motion of moon around the earth in circular path an accelerated motion?
Name the force acting away from the centre of circular path.
Name the type of energy possessed by a
(i) stretched catapult (ii) hot iron
(iii) wound up clock
Give an example
Light energy changes to electrical energy.
How long should an electric motor, of power 2 H.P. operate, so as to pump 5 m3 of water from a depth of 15m. [Take g = 10 N kg−1]
