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The temperature of a wire is doubled. The Young’s modulus of elasticity ______. - Physics

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प्रश्न

The temperature of a wire is doubled. The Young’s modulus of elasticity ______.

पर्याय

  • will also double.

  • will become four times.

  • will remain same.

  • will decrease.

MCQ
रिकाम्या जागा भरा
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उत्तर

The temperature of a wire is doubled. The Young’s modulus of elasticity will decrease.

Explanation:

Young's modulus (Y): It is defined as the ratio of normal stress to longitudinal strain within the limit of proportionality.

`Y = "Normal stress"/"Longitudinal strain"`

= `(F/A)/((ΔL)/L)`

= `(FL)/(AΔL)`

The fractional change in length of any material is defined as `(ΔL)/L_0 = αΔT` where ΔT is the change in the temperature, L0 is the original length, α is the coefficient of linear expansion of the given material and L0 is the original length of material.

So, simply a change in length is due to change in temperature.

`ΔL = L_0αΔT`

And Young's modules 

(Y) = `"Stress"/"Strain"`

= `(FL_0)/(A xx ΔL)` 

= `(FL_0)/(AL_0 ΔT) ∝ 1/(ΔT)`

As Y ∝ 1/∆T

When temperature increases ∆T increases, hence Y decreases.

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पाठ 9: Mechanical Properties of Solids - Exercises [पृष्ठ ६५]

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एनसीईआरटी एक्झांप्लर Physics [English] Class 11
पाठ 9 Mechanical Properties of Solids
Exercises | Q 9.3 | पृष्ठ ६५

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