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प्रश्न
The Sum of first five multiples of 3 is ______.
पर्याय
45
55
15
75
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उत्तर
The Sum of first five multiples of 3 is 45.
Explanation:-
The given sequence is 3, 6, 9,...
Here,
a = 3
d = 3
n = 5
Therefore,
`S_n = n/2 [2a + (n - 1) d]`
`S_5 = 5/2 [2a + (5 - 1) d]`
= `5/2 (2(3) + 4(3))`
= `5/2 (6 + 12)`
= `5/2 (18)`
= 5 × 9
= 45
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Q.5
Find the sum of natural numbers between 1 to 140, which are divisible by 4.
Activity: Natural numbers between 1 to 140 divisible by 4 are, 4, 8, 12, 16,......, 136
Here d = 4, therefore this sequence is an A.P.
a = 4, d = 4, tn = 136, Sn = ?
tn = a + (n – 1)d
`square` = 4 + (n – 1) × 4
`square` = (n – 1) × 4
n = `square`
Now,
Sn = `"n"/2["a" + "t"_"n"]`
Sn = 17 × `square`
Sn = `square`
Therefore, the sum of natural numbers between 1 to 140, which are divisible by 4 is `square`.
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