मराठी

The real value of α for which the expression 1-isinα1+2isinα is purely real is ______.

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प्रश्न

The real value of α for which the expression `(1 - i sin alpha)/(1 + 2i sin alpha)` is purely real is ______.

पर्याय

  • `(n + 1)  pi/2`

  • `(2n + 1)  pi/2`

  • None of these, where n ∈N

MCQ
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उत्तर

The real value of α for which the expression `(1 - i sin alpha)/(1 + 2i sin alpha)` is purely real is .

Explanation:

Let z = `(1 - i sin alpha)/(1 + 2i sin alpha)`

= `((1 - i sin alpha)(1 - 2i sin alpha))/((1 + 2i sin alpha)(1 - 2i sin alpha))`

= `(1 - 2i sin alpha - i sin alpha + 2i^2 sin^2 alpha)/((1)^2 - (2i sin alpha)^2`

= `(1 - 3i sin alpha - 2 sin^2 alpha)/(1 - 4i^2 sin^2 alpha)`

= `((1 - 2 sin^2 alpha) - 3i sin alpha)/(1 + 4 sin^2 alpha)`

= `(1 - 2 sin^2 alpha)/(1 + 4 sin^2 alpha) - (3sin alpha)/(1 + 4 sin^2 alpha) .i`

Since, z is purely real.

Then `(-3 sin alpha)/(1 + 4 sin^2 alpha)` = 0

⇒ sinα = 0

So, α = nπ, n ∈ N.

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पाठ 5: Complex Numbers and Quadratic Equations - Exercise [पृष्ठ ९५]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
पाठ 5 Complex Numbers and Quadratic Equations
Exercise | Q 36 | पृष्ठ ९५

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