Advertisements
Advertisements
प्रश्न
The radius of a circle is 6 cm. The perpendicular distance from the centre of the circle to the chord which is 8 cm in length, is
पर्याय
- \[\sqrt{5} \] cm
- \[2\sqrt{5}\] cm
\[2\sqrt{7} \] cm
- \[\sqrt{7}\] cm
Advertisements
उत्तर
We will represent the given data in the figure
We know that perpendicular drawn from the centre to the chord divides the chord into two equal parts.
So , AM = MB = \[\frac{AB}{2} = \frac{8}{2}\] = 4 cm.
Using Pythagoras theorem in the ΔAMO,
`OM^2 = AO^2 - AM^2`
`= 6^2 - 4^2`
= 36-16
`= sqrt(20)`
= `2sqrt(5)` cm
APPEARS IN
संबंधित प्रश्न
ABCD is a quadrilateral such that ∠D = 90°. A circle (O, r) touches the sides AB, BC, CD and DA at P,Q,R and If BC = 38 cm, CD = 25 cm and BP = 27 cm, find r.
In two concentric circles, prove that all chords of the outer circle which touch the inner circle are of equal length.
A chord of a circle of radius 14 cm subtends an angle of 120° at the centre. Find the area of the corresponding minor segment of the circle. `[User pi22/7 and sqrt3=1.73]`
If O is the centre of a circle of radius r and AB is a chord of the circle at a distance r/2 from O, then ∠BAO =
In the given figure, AB is a diameter of a circle with centre O and AT is a tangent. If \[\angle\] AOQ = 58º, find \[\angle\] ATQ.
Construct a triangle ABC with AB = 4.2 cm, BC = 6 cm and AC = 5cm. Construct the circumcircle of the triangle drawn.
If O is the center of the circle in the figure alongside, then complete the table from the given information.
The type of arc
| Type of circular arc | Name of circular arc | Measure of circular arc |
| Minor arc | ||
| Major arc |
AB and AC are two equal chords of a circle. Prove that the bisector of the angle BAC passes through the centre of the circle.
Two chords AB and AC of a circle subtends angles equal to 90º and 150º, respectively at the centre. Find ∠BAC, if AB and AC lie on the opposite sides of the centre.
Which of the following describes the radius of a circle?
