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प्रश्न
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उत्तर
Radius of one circular end, r1 = 14 cm
Radius of other circular end, r2 = 7 cm
Height of the bucket, h = 30 cm
∴ Volume of water in the bucket = Volume of frustum of cone
\[= \frac{1}{3}\pi h\left( r_1^2 + r_1 r_2 + r_2^2 \right)\]
\[ = \frac{1}{3} \times \frac{22}{7} \times 30 \times \left( {14}^2 + 14 \times 7 + 7^2 \right)\]
\[ = \frac{1}{3} \times \frac{22}{7} \times 30 \times 343\]
\[ = 10780 {cm}^3\]
\[= \frac{10780}{1000}\] ...[∵ 1 litre = 1000cm3]
= 10.78 L
Thus, the bucket can hold 10.78 litres of water.
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