मराठी

The Radii of the Circular Ends of a Solid Frustum of a Cone Are 33 Cm and 27 Cm and Its Slant Height is 10 Cm. Find Its Total Surface Area. Use π = 3.14. - Mathematics

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प्रश्न

The radii of the circular ends of a solid frustum of a cone are 33 cm and 27 cm and its slant height is 10 cm. Find its total surface area. [Use π = 3.14.]

बेरीज
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उत्तर

Greater radius = R = 33 cm

Smaller radius = r = 27 cm

Slant height = l = 10 cm

Surface area of the frustum

= πR2 + πr2 + πl (R + r)

= π [R2 + r2 + l (R+r)]

= [332 + 272 + 10(33 + 27)]π

= [1089 + 729 + 10(60)] π

= 2418 × 3.14

= 7592.52 cm2

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पाठ 19: Volume and Surface Area of Solids - Exercise 19C [पृष्ठ ९११]

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आर. एस. अग्रवाल Mathematics [English] Class 10
पाठ 19 Volume and Surface Area of Solids
Exercise 19C | Q 13 | पृष्ठ ९११
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