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The Perimeter of the Triangle Formed by the Points (0, 0), (0, 1) and (0, 1) is - Mathematics

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प्रश्न

The perimeter of the triangle formed by the points (0, 0), (0, 1) and (0, 1) is 

पर्याय

  •  1 ± \[\sqrt{2}\]

     

  • \[\sqrt{2}\]  + 1

     

  • 3

  • \[2 + \sqrt{2}\]

     

MCQ
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उत्तर

We have a triangle ΔABC  whose co-ordinates are A (0, 0); B (1, 0); C (0, 1). So clearly the triangle is right angled triangle, right angled at A. So,

AB = 1 unit

AC = 1 unit

Now apply Pythagoras theorem to get the hypotenuse,

`BC = sqrt(AB^2 + Ac^2 )`

       `= sqrt(2)`

So the perimeter of the triangle is,

= AB + BC + AC 

`= 1 + 1+ sqrt(2)`

`= 2  + sqrt(2)`

 

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पाठ 6: Co-Ordinate Geometry - Exercise 6.7 [पृष्ठ ६३]

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आरडी शर्मा Mathematics [English] Class 10
पाठ 6 Co-Ordinate Geometry
Exercise 6.7 | Q 7 | पृष्ठ ६३

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