Question

The perimeter of the triangle formed by the points (0, 0), (0, 1) and (0, 1) is 

पर्याय

•  1 ± \[\sqrt{2}\]

   

• \[\sqrt{2}\]  + 1

   

• 3

• \[2 + \sqrt{2}\]

   

Answer 1

We have a triangle ΔABC  whose co-ordinates are A (0, 0); B (1, 0); C (0, 1). So clearly the triangle is right angled triangle, right angled at A. So,

AB = 1 unit

AC = 1 unit

Now apply Pythagoras theorem to get the hypotenuse,

`BC = sqrt(AB^2 + Ac^2 )`

       `= sqrt(2)`

So the perimeter of the triangle is,

= AB + BC + AC 

`= 1 + 1+ sqrt(2)`

`= 2  + sqrt(2)`