Advertisements
Advertisements
प्रश्न
The perimeter of a rectangular plot is 180 m and its area is 1800 m2. Take the length of the plot as x m. Use the perimeter 180 m to write the value of the breadth in terms of x. Use the values of length, breadth and the area to write an equation in x. Solve the equation to calculate the length and breadth of the plot.
Advertisements
उत्तर
The perimeter of a rectangular field = 180m
and area = 1800m2
Let length = xm
But length + breadth = `(180)/(2)` = 90m
∴ breadth = (90 - x)m
According to the condition,
x(90 - x) = 1800
⇒ 90x - x2 - 1800 = 0
⇒ x2 - 90x + 1800 = 0
⇒ x2 - 60x - 30x + 1800 = 0
⇒ x(x - 60) - 30(x - 60) = 0
⇒ (x - 60)(x - 30) = 0
EIther x - 60 = 0,
then x = 60
or
x - 30 = 0,
then x = 30
∵ Length is greater than its breadth
∴ Length = 60m
and breadth = 90 - 60 = 30m.
APPEARS IN
संबंधित प्रश्न
Solve (i) x2 + 3x – 18 = 0
(ii) (x – 4) (5x + 2) = 0
(iii) 2x2 + ax – a2 = 0; where ‘a’ is a real number
Solve the following quadratic equations by factorization:
9x2 − 3x − 2 = 0
The sum of two number a and b is 15, and the sum of their reciprocals `1/a` and `1/b` is 3/10. Find the numbers a and b.
Solve the following quadratic equation by factorisation.
2y2 + 27y + 13 = 0
If \[x^2 + k\left( 4x + k - 1 \right) + 2 = 0\] has equal roots, then k =
Solve the following equation: (x-8)(x+6) = 0
Solve the following quadratic equation by factorisation method:
`(x + 3)/(x - 2) - (1 - x)/x = (17)/(4)`.
Sum of two natural numbers is 8 and the difference of their reciprocal is `2/15`. Find the numbers.
If x = –2 is the common solution of quadratic equations ax2 + x – 3a = 0 and x2 + bx + b = 0, then find the value of a2b.
The product of two integers is –18; the integers are ______.
