मराठी

The altitude of a right triangle is 7 cm less than its base. If the hypotenuse is 13 cm, find the other two sides. - Mathematics

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प्रश्न

The altitude of a right triangle is 7 cm less than its base. If the hypotenuse is 13 cm, find the other two sides.

बेरीज
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उत्तर

Using Pythagoras Theorem

`"(hypotenuse)"^2 = sqrt("(height)"^2 + "(base)"^2)`

`AC^2 = sqrt(AB^2 + BC^2)`

`(13)^2 =sqrt( (x )^2 + (x - 7)^2)`

169 = x2 + (x - 7)2

169 = x2 + x2 - 14x + 49

2x2 - 14x - 120 = 0

x2 - 7x - 60 = 0

x2 - 12x + 5x - 60 = 0

x(x - 12) + 5(x - 12) = 0

(x - 12)(x + 5) = 0

Either x - 12 = 0 or x + 5 = 0

x = 12 or x = - 5

Since

Base of right angled triangle = x cm = 12 cm

Right triangle height = x – 7 cm

= 12 - 7

= 5 cm

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पाठ 4: Quadratic Equations - EXERCISE 4.2 [पृष्ठ ४४]

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एनसीईआरटी Mathematics [English] Class 10
पाठ 4 Quadratic Equations
EXERCISE 4.2 | Q 5. | पृष्ठ ४४

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