Advertisements
Advertisements
प्रश्न
The marginal cost function is MC = `300 x^(2/5)` and fixed cost is zero. Find out the total cost and average cost functions
Advertisements
उत्तर
MC = `300 x^(2/5)` and fixed cost k = 0
Total cost t = `int"MC" "d"x`
C = `int300 x^(2/5) "d"x`
= `300 (x^(2/5 + 1))/((2/5 + 1)) + "k"`
C = `300[x^(7/5)/((7/5))] + 0`
∴ C = `1500/7 x^(7/5)`
Average cost A.C = `"C"/x = (1500/7 x^(7/5))/x`
A.C = `1500/7 x^(7/5 - 1)`
∴ A.C = `1500/7 x^(2/5)`
APPEARS IN
संबंधित प्रश्न
Elasticity of a function `("E"y)/("E"x)` is given by `("E"y)/("E"x) = (-7x)/((1 - 2x)(2 + 3x))`. Find the function when x = 2, y = `3/8`
If the marginal cost (MC) of production of the company is directly proportional to the number of units (x) produced, then find the total cost function, when the fixed cost is ₹ 5,000 and the cost of producing 50 units is ₹ 5,625
Calculate consumer’s surplus if the demand function p = 122 – 5x – 2x2, and x = 6
If the supply function for a product is p = 3x + 5x2. Find the producer’s surplus when x = 4
The demand and supply functions under perfect competition are pd = 1600 – x2 and ps = 2x2 + 400 respectively. Find the producer’s surplus
Choose the correct alternative:
The marginal revenue and marginal cost functions of a company are MR = 30 – 6x and MC = – 24 + 3x where x is the product, then the profit function is
Choose the correct alternative:
When x0 = 5 and p0 = 3 the consumer’s surplus for the demand function pd = 28 – x2 is
Choose the correct alternative:
If MR and MC denote the marginal revenue and marginal cost and MR – MC = 36x – 3x2 – 81, then the maximum profit at x is equal to
Choose the correct alternative:
If the marginal revenue of a firm is constant, then the demand function is
For the marginal revenue function MR = 6 – 3x2 – x3, Find the revenue function and demand function
