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प्रश्न
The following table shows the electronic configuration of the atoms A, B, C and D.
| Element | A | B | C | D |
| Electronic configuration | 2, 8, 8, 2 | 2, 6 | 2, 8, 7 | 2, 4 |
- Write the formula of the compound formed between:
- A and B
- D and C
- Which of the above elements will exhibit catenation?
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उत्तर
(a) (1)
| Electronic Configuration | Valency | |
| A : | 2, 8, 8, 2 | + 2 |
| B : | 2, 6 | - 2 |
Formula: AB
(2)
| Electronic Configuration | Valency | |
| D : | 2, 4 | ± 4 |
| C : | 2, 8, 7 | - 1 |
Formula: DC4
(b) 'D' will exhibit catenation.
संबंधित प्रश्न
Draw an electron dot diagram for the formation of the following. State the type of bonding present in them.
Ammonium ion
Covalent bond is formed by ______
Polar solvents contain bonds between atoms with ______.
______ & ______ atoms have similar electronegativities.
Spot the error/correct the wrong statement:
Covalent compounds are soluble in polar solvents.
Draw the electron dot structure for the following:
A molecular nitrogen
[At. No. : N = 7, H = 1]
Draw the electron dot structure of Nitrogen molecule.
[Atomic number: N = 7, C = 6, H = 1]
Carbon tetrachloride is a ______ covalent molecule.
Draw the structure for carbon tetrachloride and explain the type of bonding present.
Select the right answer.
Ammonium ion
