Question

Ammonia burns in oxygen, as shown below.

\[\ce{4NH3 + 3O2 -> 2N2 + 6H2O}\]

If 240 cc of ammonia is burnt in 300 cc of oxygen, find out the composition of the resultant gaseous mixture at room temperature.

Answer 1

\[\ce{4NH3 + 3O2 -> 2N2 + 6H2O}\] (vapour)

By Gay Lussac's Law

For N₂:

4 vol. of NH₃ results 2 vol. of N₂

240 cc of NH₃ will result = `(2 xx 240)/4`

= 120 cc of N₂

For H₂O (vapour phase):

4 Vol. of NH₃ results 6 vol. of H₂O

240 cc of NH₃ will result = `(240 xx 6)/4`

= 360 cc of H₂O

For O₂:

4 vol. of NH₃ reacts with 3 vol. of H₂O

240 cc of NH₃ will react with = `(3 xx 240)/4`

= 180 cc of O₂