Advertisements
Advertisements
प्रश्न
The following expression is the area of a rectangle. Find the possible length and breadth of the rectangle.
x2 – 6x + 8
Advertisements
उत्तर
Given, area of a rectangle = x2 – 6x + 8
Now, we have to find the possible length and breadth of the rectangle.
So, we factorise the given expression.
i.e. x2 – 6x + 8 = x2 – (4 + 2)x + 8
= x2 – 4x – 2x + 8
= x(x – 4) – 2(x – 4)
= (x – 4)(x – 2)
Since, area of a rectangle = Length × Breadth.
Hence, the possible length and breadth are (x – 4) and (x – 2).
APPEARS IN
संबंधित प्रश्न
Expand.
(p + 8) (p − 3)
Expand.
(9x − 5t) (9x + 3t)
Expand.
`(m + 2/3)(m − 7/3)`
Expand: (x + 2)(x + 3).
Expand (2n – 1)(2n + 3)
Using the identity (x + a)(x + b) = x2 + x(a + b) + ab, find the following product
(4x + 3y)(4x + 5y)
Simplify using identities
(3p + q)(3p + r)
Using suitable identities, evaluate the following.
104 × 97
The following expression is the area of a rectangle. Find the possible length and breadth of the rectangle.
x2 – 7x + 10
The following expression is the area of a rectangle. Find the possible length and breadth of the rectangle.
x2 + 9x + 20
