Advertisements
Advertisements
प्रश्न
Expand.
(a + 2) (a − 1)
बेरीज
Advertisements
उत्तर
Given:
(a + 2) (a – 1)
x = a
The first constant (a) = 2
The second constant (b) = –1
(x + a) (x + b) = x2 + (a + b)x + ab
Apply the identity
(a)2 + [2 + (–1)]a + (2 × –1)
Simplify the brackets
2 + (–1) = 1
2 × –1 = –2
Write the final terms
a2 + 1a – 2
(a + 2) (a – 1)
= a2 + a – 2
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
संबंधित प्रश्न
Expand.
(p + 8) (p − 3)
Expand.
(13 + x) (13 − x)
Expand.
(9x − 5t) (9x + 3t)
Use the Identity (x + a)(x + b) = x2 + (a + b)x + ab to find the following:
501 × 502
Expand: (x + 2)(x + 3).
Expand (2n – 1)(2n + 3)
Using the identity (x + a)(x + b) = x2 + x(a + b) + ab, find the following product
(4x + 3y)(4x + 5y)
Using the identity (x + a)(x + b) = x2 + x(a + b) + ab, find the following product
(8 + pq)(pq + 7)
Using suitable identities, evaluate the following.
101 × 103
The following expression is the area of a rectangle. Find the possible length and breadth of the rectangle.
x2 + 19x – 20
