Question

The electric force experienced by a charge of 1.0 × 10⁻⁶ C is 1.5 × 10⁻³ N. Find the magnitude of the electric field at the position of the charge.

Answer 1

Given:
Magnitude of the charges, q =  1.0 × 10⁻⁶ C
Electric force, F = 1.5 × 10⁻³ N
We know that F = qE

\[\Rightarrow E = \frac{F}{q} = \frac{1 . 5 \times {10}^{- 3}}{1 . 0 \times {10}^{- 6}}  \] 

\[                   = 1 . 5 \times  {10}^3\]N/C