Advertisements
Advertisements
प्रश्न
The distance-time values for an object moving along straight line are given below:
| Time (s) | Distance (m) |
| 0 | 0 |
| 1 | 1 |
| 2 | 8 |
| 3 | 27 |
Advertisements
उत्तर
| Time (s) | Distance (m) | Velocity (ms-1)= distance/time | Acceleration (ms-1)= (v-u)/(t2-t1) |
| 0 | 0 | 0 | 0 |
| 1 | 1 | 1 | 1 |
| 2 | 8 | 4 | 3 |
| 3 | 27 | 9 | 5 |
So the object moves with increasing acceleration
APPEARS IN
संबंधित प्रश्न
Answer the following:
You can shield a charge from electrical forces by putting it inside a hollow conductor. Can you shield a body from the gravitational influence of nearby matter by putting it inside a hollow sphere or by some other means?
State two applications of universal law of gravitation.
All objects in the universe attract each other along the line joining their________.
Why don't you feel the force of attraction between your friend sitting close to you and yourself?
A force can produce ________, In an object at rest. It can __________ an object and change its __________ of motion.
Gravity is another kind of ________. It exerts all through the ________. The Sun's gravity keeps the ___________ in their orbits. Gravity can only be felt with very large ________.
Does the force of the earth's gravitation affect the motion of the moon? Explain your answer with reasons.
Mahendra and Virat are sitting at a distance of 1m from each other. Their masses are 75 kg and 80 kg respectively. What is the gravitational force between them? (G = 6.67 × 10−11 Nm2/kg2)
For the weight of body of mass 5 kg to be zero on equator of the earth, angular velocity of the earth must be (The radius of earth = 6400 km, acceleration due to gravity = 10 m/s2).
For an object outside a uniform solid sphere, from where is the sphere's mass considered to act?
