Advertisements
Advertisements
प्रश्न
The diagram above shows a circuit with the key k open. Calculate :
(i) the resistance of the circuit when the key k is open.
(ii) the current drawn from the cell when the key k is open.
(iii) the resistance of the circuit when the key k is closed.
(iv) the current drawn from the cell when the key k is closed.
Advertisements
उत्तर
(i) when k is open
Req = 5Ω + 0.5 Ω = 5.5Ω
(ii) `i = v/(R_(eq))|_("case k open")`
`=(3.3v)/(5.5 Ω ) = 3/5 =0.6 A`
(iii) when k is closed,
`R_(eq) =(R_1R_2)/(R_1 + R_2) = (5xx5)/(5+5) = 2.5 Ω`
`R_(Total) = 2.5 Ω + 0.5 Ω = 3.0 Ω`
(iv) `i =v/(R_T) = 3.3/3.0 = 1.1A`
APPEARS IN
संबंधित प्रश्न
Which uses more energy, a 250 W TV set in 1 hr, or a 1200 W toaster in 10 minutes?
Which uses more energy: a 250 W TV set in 1 hour or a 1200 W toaster in 10 minutes?
Which of the following is likely to be the correct wattage for an electric iron used in our homes?
(a) 60 W
(b) 250 W
(c) 850 W
(d) 2000 W
An electric heater of resistance 8 Ω takes a current of 15 A from the mains supply line. Calculate the rate at which heat is developed in the heater.
A servo voltage stabiliser restricts the voltage output to 220 V ± 1%. If an electric bulb rated at 220 V, 100 W is connected to it, what will be the minimum and maximum power consumed by it?
An electric bulb marked 220 V, 100 W will get fused if it is made to consume 150 W or more. What voltage fluctuation will the bulb withstand?
An electric bulb is rated as 100W – 250V. What information does it convey? Calculate the current through the filament of the bulb.
What is the commercial unit of electrical energy?
