Advertisements
Advertisements
प्रश्न
The curved surface area of a cylinder is 2π(y2 – 7y + 12) and its radius is (y – 3). Find the height of the cylinder (C.S.A. of cylinder = 2πrh).
Advertisements
उत्तर
Let the height of cylinder be h.
Given, the curved surface area of a cylinder = 2π(y2 – 7y + 12)
And radius of cylinder = y – 3
We know that,
Curved surface area of cylinder = 2πrh
∴ 2πrh = 2π(y2 – 7y + 12)
⇒ 2πrh = 2π(y2 – 4y – 3y + 12)
= 2π[y(y – 4) – 3(y – 4)]
= 2π(y – 3)(y – 4)
⇒ 2πh = 2πr(y – 4) ...[∵ r = (y – 3), given)]
On comparing the both sides, we get h = y – 4
Hence, the height of the cylinder is y – 4.
APPEARS IN
संबंधित प्रश्न
Expand (2)2p − 3q
Expand (5p – 1)2
Factors of 4 – m2 are
(p – q)2 = _______________
Factorised form of 4y2 – 12y + 9 is ______.
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
x2 – 8x + 16
Factorise the following.
y2 + 4y – 21
Factorise the following.
x2 – 10x + 21
If m – n = 16 and m2 + n2 = 400, then find mn.
Verify the following:
(a – b)(a – b)(a – b) = a3 – 3a2b + 3ab2 – b3
