Advertisements
Advertisements
प्रश्न
The area of a square is given by 4x2 + 12xy + 9y2. Find the side of the square.
Advertisements
उत्तर
We have,
Area of square = 4x2 + 12xy + 9y2
So, we factorise the given expression.
∴ 4x2 + 12xy + 9y2 = (2x)2 + 2 × 2x × 3y + (3y)2 ...[∵ a2 + 2ab + b2 = (a + b)2]
= (2x + 3y)2
Since, area of a square having side length a is a2.
Hence, side of the given square is 2x + 3y.
APPEARS IN
संबंधित प्रश्न
Simplify (2x +5)2 − (2x − 5)2
Expand `("x"+1/2)^2`
Use the formula to multiply the following.
`(x/5+6)(x/5-6)`
Use a formula to multiply of (2t – 5)(2t + 5)
Factors of 9x2 + 6xy are
If a + b = 5 and a2 + b2 = 13, then ab = ?
(a + b)2 – 2ab = ______ + ______.
Factorise the following.
y2 + 18x + 65
Factorise the following.
18 + 11x + x2
The area of a rectangle is x2 + 7x + 12. If its breadth is (x + 3), then find its length.
