Advertisements
Advertisements
प्रश्न
The area of a square is given by 4x2 + 12xy + 9y2. Find the side of the square.
Advertisements
उत्तर
We have,
Area of square = 4x2 + 12xy + 9y2
So, we factorise the given expression.
∴ 4x2 + 12xy + 9y2 = (2x)2 + 2 × 2x × 3y + (3y)2 ...[∵ a2 + 2ab + b2 = (a + b)2]
= (2x + 3y)2
Since, area of a square having side length a is a2.
Hence, side of the given square is 2x + 3y.
APPEARS IN
संबंधित प्रश्न
Find the following squares by suing the identities
(0.4p − 0.5q)2
Using identities, evaluate 297 × 303
Expand: (2x + 3y)2
Expand: (51)2
If a + b = 10 and ab = 18, find the value of a2 + b2
If a + b = 5 and a2 + b2 = 13, then ab = ?
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
x2 + 14x + 49
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
a2x2 + 2abxy + b2y2
The area of a square is 9x2 + 24xy + 16y2. Find the side of the square.
What should be added to 4c(– a + b + c) to obtain 3a(a + b + c) – 2b(a – b + c)?
