Advertisements
Advertisements
प्रश्न
Expand `("x"+1/2)^2`
योग
Advertisements
उत्तर
It is known that (a + b)2 = a2 + 2ab + b2 and (a − b)2 = a2 − 2ab + b2.
`("x"+1/2)^2`
= `("x")^2+2xx("x")xx(1/2)+(1/2)^2`
= `"x"^2+"x"+1/4`
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
संबंधित प्रश्न
Use a suitable identity to get the following products.
(1.1m − 0.4) (1.1 m + 0.4)
Find the following squares by suing the identities.
(6x2 − 5y)2
Simplify (a2 − b2)2
Simplify (4m + 5n)2 + (5m + 4n)2
Using a2 − b2 = (a + b) (a − b), find (1.02)2 − (0.98)2
Expand `("a"/2+"b"/3)^2`
Expand: (51)2
The sum of areas of two squares with sides 4a and 4b is ______.
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
x2 + 14x + 49
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
a2x2 + 2abxy + b2y2
