मराठी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान इयत्ता ११

The Angle Between the Resultant Contact Force and the Normal Force Exerted by a Body on the Other is - Physics

Advertisements
Advertisements

प्रश्न

The angle between the resultant contact force and the normal force exerted by a body on the other is called the angle of friction. Show that, if λ be the angle of friction and μ the coefficient of static friction λ ≤ tan−1 μ.

बेरीज
Advertisements

उत्तर

Let
 f  be the applied force,
R  be the normal reaction force and
F  be the frictional force.

The coefficient of static friction is given by
`u = tanlambda = "F"/"R"`
(where λ is the angle of friction)
When F = μR, F is the limiting friction (maximum friction). When applied force increases and the body still remains still static then the force of friction increases up to its maximum value equal to limiting friction (μR).
F < μR
`thereforetanlambda="F"/"R"<=(muR)/R`
⇒ tan λ ≤ μ
⇒ λ ≤ tan−1 μ

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 6: Friction - Exercise [पृष्ठ ९७]

APPEARS IN

एचसी वर्मा Concepts of Physics Vol. 1 [English] Class 11 and 12
पाठ 6 Friction
Exercise | Q 10 | पृष्ठ ९७
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×