मराठी

The amplitude of the magnetic field of a plane electromagnetic wave propagating along positive X axis in vacuum is 510 nThat k and its angular frequency is 60 × 10^6 rad/sec. - Physics

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प्रश्न

The amplitude of the magnetic field of a plane electromagnetic wave propagating along the positive X axis in a vacuum is 510 nT`hat k` and its angular frequency is 60 × 106 rad/sec. Write the expression for the electric field `(vec E)`.

संख्यात्मक
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उत्तर

Given: Bo = 510 nT = 510 × 10−9 T

ω = 60 × 106 rad/sec

c = 3 × 108 m/s

Eo = cBo

= 3 × 10× 510 × 10−9

= 153 N/C

k = `ω/c`

= `(60 xx 10^6)/(3 xx 10^8)`

= 20 × 10−2 rad/m

The general expression for the electric field of a plane electromagnetic wave propagating along the x-axis is

`vec E(x, t) = E_o sin(omega t - kx)`

= 153 sin(60 × 106 t − 20 × 10−2 x) N/C 

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