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प्रश्न
The amplitude of the magnetic field of a plane electromagnetic wave propagating along the positive X axis in a vacuum is 510 nT`hat k` and its angular frequency is 60 × 106 rad/sec. Write the expression for the electric field `(vec E)`.
संख्यात्मक
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उत्तर
Given: Bo = 510 nT = 510 × 10−9 T
ω = 60 × 106 rad/sec
c = 3 × 108 m/s
Eo = cBo
= 3 × 108 × 510 × 10−9
= 153 N/C
k = `ω/c`
= `(60 xx 10^6)/(3 xx 10^8)`
= 20 × 10−2 rad/m
The general expression for the electric field of a plane electromagnetic wave propagating along the x-axis is
`vec E(x, t) = E_o sin(omega t - kx)`
= 153 sin(60 × 106 t − 20 × 10−2 x) N/C
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