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рдкреНрд░рд╢реНрди
`(tan A + tanB )/(cot A + cot B) = tan A tan B`
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LHS = `(tan A + tanB )/(cot A + cot B) `
=`(tan A + tan B)/(1/ tan A + 1/ tanB)`
=` (tan A + tan B)/( (tan A+tan B)/ (tan A tan B)`
=`(tan A tan B ( tan A + tan B))/((tan A + tan B ))`
= ЁЭСбЁЭСОЁЭСЫЁЭР┤ ЁЭСбЁЭСОЁЭСЫЁЭР╡
= RHS
Hence, LHS = RHS
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Define an identity.
If sin2 θ cos2 θ (1 + tan2 θ) (1 + cot2 θ) = λ, then find the value of λ.
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`sinθ(1 + tanθ) + cosθ(1 +cotθ) = secθ + cosecθ`
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`tan ((B + C)/2) = cot "A/2`
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cot θ . tan θ = ?
(sec θ + tan θ) . (sec θ – tan θ) = ?
Prove that `sqrt((1 + cos A)/(1 - cos A)) = "cosec" A + cot A`.
Prove the following that:
`tan^3θ/(1 + tan^2θ) + cot^3θ/(1 + cot^2θ)` = secθ cosecθ – 2 sinθ cosθ
Factorize: sin3θ + cos3θ
Hence, prove the following identity:
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