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प्रश्न
Taking x = `(-4)/9`, y = `5/12` and z = `7/18`, find (x – y) + z.
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उत्तर
Given, x = `(-4)/9`, y = `5/12` and z = `7/18`
We have, (x – y) + z = `((-4)/9 - 5/12) + 7/18`
= `(-4 xx 4 - 5 xx 3)/36 + 7/18` ...[∵ LCM of 9 and 12 = 36]
= `(-16 - 15)/36 + 7/18`
= `((-31)/36 + 7/18)`
= `(-31 + 7 xx 2)/36`
= `(-31 + 14)/36`
= `(-17)/36`
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संबंधित प्रश्न
Find the value of `(-1)/8 ÷ 3/4`.
Evaluate:
`3 ÷ 3/5`
The product of two numbers is `(-4)/9`. If one of them is` (-2)/27`, find the other.
Divide:
`(-5)/8 "by" 1/4`
If `3 1/2` litres of milk costs ₹49, find the cost of one litre of milk?
Find (m + n) ÷ (m - n), if:
m = `3/4` and n = `4/3`
Divide the sum of `5/8` and `(-11)/12` by the difference of `3/7` and `5/14`.
Match the following:
| Column I | Column II |
| (i) `a/b ÷ a/b` | (a) `(-a)/b` |
| (ii) `a/b ÷ c/d` | (b) –1 |
| (iii) `a/b ÷ (-1)` | (c) 1 |
| (iv) `a/b ÷ (-a)/b` | (d) `(bc)/(ad)` |
| (v) `b/a ÷ (d/c)` | (e) `(ad)/(bc)` |
Simplify:
`3/7 ÷ (21/-55)`
Taking x = `(-4)/9`, y = `5/12` and z = `7/18`, find x ÷ (y ÷ z).
