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प्रश्न
Taking x = `(-4)/9`, y = `5/12` and z = `7/18`, find (x ÷ y) × z.
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उत्तर
Given, x = `(-4)/9`, y = `5/12` and z = `7/18`
We have, (x ÷ y) × z
= `((-4)/9 ÷ 5/12) xx 7/18`
= `((-4)/9 xx 12/5) xx 7/18` ...`[∵ "Reciprocal of" 5/12 = 12/5]`
= `(-4 xx 12 xx 7)/(9 xx 5 xx 18)` ...`[∵ "Product of rational numbers" = "Product of numerators"/"Product of denominators"]`
= `(-56)/135`
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संबंधित प्रश्न
Find the value of `(-1)/8 ÷ 3/4`.
Divide the sum of `3/7` and `(-5)/14` by `(-1)/2`
Divide the sum of `5/8` and `(-11)/12` by the difference of `3/7` and `5/14`.
Find (a + b) ÷ (a – b) if a = `1/2`, b = `2/3`
Simplify:
`13/11 xx (-14)/5 + 13/11 xx (-7)/5 + (-13)/11 xx 34/5`
Simplify:
`6/5 xx 3/7 - 1/5 xx 3/7`
Find the reciprocal of the following:
`3/13 ÷ (-4)/65`
Find the reciprocal of the following:
`(-5 xx 12/15) - (-3 xx 2/9)`
Taking x = `(-4)/9`, y = `5/12` and z = `7/18`, find the sum of reciprocals of x and y.
Taking x = `(-4)/9`, y = `5/12` and z = `7/18`, find (x – y) + z.
