Advertisements
Advertisements
प्रश्न
Suppose three parts of 207 are (a − d), a , (a + d) such that , (a + d) >a > (a − d).
Advertisements
उत्तर
\[a - d + a + a + d = 207\]
\[ \Rightarrow 3a = 207\]
\[ \Rightarrow a = 69\]
\[Now, \left( a - d \right) \times a = 4623\]
\[ \Rightarrow 69\left( 69 - d \right) = 4623\]
\[ \Rightarrow \left( 69 - d \right) = 67\]
\[ \Rightarrow d = 2\]
\[\text{ Therefore, the three required parts are 67, 69 and 71} .\]
APPEARS IN
संबंधित प्रश्न
If the term of m terms of an A.P. is the same as the sum of its n terms, show that the sum of its (m + n) terms is zero
How many terms of the AP. 9, 17, 25 … must be taken to give a sum of 636?
Which term of the A.P. 121, 117, 113 … is its first negative term?
[Hint: Find n for an < 0]
Find the sum of the following arithmetic progressions:
a + b, a − b, a − 3b, ... to 22 terms
Find the sum of all 3-digit natural numbers, which are multiples of 11.
Find the sum 25 + 28 + 31 + ….. + 100
Find the middle term of the AP 10, 7, 4, ……., (-62).
The 9th term of an AP is -32 and the sum of its 11th and 13th terms is -94. Find the common difference of the AP.
How many numbers are there between 101 and 999, which are divisible by both 2 and 5?
The sum of the first n terms of an AP in `((5n^2)/2 + (3n)/2)`.Find its nth term and the 20th term of this AP.
How many terms of the AP 63, 60, 57, 54, ….. must be taken so that their sum is 693? Explain the double answer.
In an A.P. 17th term is 7 more than its 10th term. Find the common difference.
First term and the common differences of an A.P. are 6 and 3 respectively; find S27.
Solution: First term = a = 6, common difference = d = 3, S27 = ?
Sn = `"n"/2 [square + ("n" - 1)"d"]` - Formula
Sn = `27/2 [12 + (27 - 1)square]`
= `27/2 xx square`
= 27 × 45
S27 = `square`
For an given A.P., t7 = 4, d = −4, then a = ______.
Choose the correct alternative answer for the following question .
If for any A.P. d = 5 then t18 – t13 = ....
If m times the mth term of an A.P. is eqaul to n times nth term then show that the (m + n)th term of the A.P. is zero.
If the seventh term of an A.P. is \[\frac{1}{9}\] and its ninth term is \[\frac{1}{7}\] , find its (63)rd term.
If \[\frac{5 + 9 + 13 + . . . \text{ to n terms} }{7 + 9 + 11 + . . . \text{ to (n + 1) terms}} = \frac{17}{16},\] then n =
Find the common difference of an A.P. whose first term is 5 and the sum of first four terms is half the sum of next four terms.
Measures of angles of a triangle are in A.P. The measure of smallest angle is five times of common difference. Find the measures of all angles of a triangle. (Assume the measures of angles as a, a + d, a + 2d)
